x^2=(-2x)=(-15

Solution for x^2=(-2x)=(-15 equation:

x^2=(-2x)=(-15

We move all terms to the left:

x^2-((-2x))=0


We calculate terms in parentheses: -((-2x)), so:

(-2x)

We get rid of parentheses

-2x

Back to the equation:

-(-2x)


We get rid of parentheses

x^2+2x=0

a = 1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*1}=\frac{-4}{2}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*1}=\frac{0}{2}
=0
$